2[p-(4p+12)+4]=2(p+8)

Solution for 2[p-(4p+12)+4]=2(p+8) equation:

Simplifying
2[p + -1(4p + 12) + 4] = 2(p + 8)

Reorder the terms:
2[p + -1(12 + 4p) + 4] = 2(p + 8)
2[p + (12 * -1 + 4p * -1) + 4] = 2(p + 8)
2[p + (-12 + -4p) + 4] = 2(p + 8)

Reorder the terms:
2[-12 + 4 + p + -4p] = 2(p + 8)

Combine like terms: -12 + 4 = -8
2[-8 + p + -4p] = 2(p + 8)

Combine like terms: p + -4p = -3p
2[-8 + -3p] = 2(p + 8)
[-8 * 2 + -3p * 2] = 2(p + 8)
[-16 + -6p] = 2(p + 8)

Reorder the terms:
-16 + -6p = 2(8 + p)
-16 + -6p = (8 * 2 + p * 2)
-16 + -6p = (16 + 2p)

Solving
-16 + -6p = 16 + 2p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-2p' to each side of the equation.
-16 + -6p + -2p = 16 + 2p + -2p

Combine like terms: -6p + -2p = -8p
-16 + -8p = 16 + 2p + -2p

Combine like terms: 2p + -2p = 0
-16 + -8p = 16 + 0
-16 + -8p = 16

Add '16' to each side of the equation.
-16 + 16 + -8p = 16 + 16

Combine like terms: -16 + 16 = 0
0 + -8p = 16 + 16
-8p = 16 + 16

Combine like terms: 16 + 16 = 32
-8p = 32

Divide each side by '-8'.
p = -4

Simplifying
p = -4